//將字符串轉化成整型數值

#include

using namespace std;

int atoi(char *string)

{

int num=0;

int f=1;

if(*string=='-')

{

f=-1;

string++;

}

if(*string=='+')

{

f=1;

string++;

}

while(*string!=0&&*string>='0'&&*string<='9')

{

num=num*10+*string-'0';

string++;

}

return f*num;

}

void main()

{

char num[20];

cout<<">>num;

cout<<"轉換後的結果："<

}